Probability second green = \(\frac{4}{11}\).
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- Question:** A bag contains 3 red, 4 blue, and 5 green marbles. Two are drawn without replacement. What is the probability both are green?
- Total marbles = 12.
- Probability first green = \(\frac{5}{12}\).
- Combined: \(\frac{5}{12} \times \frac{4}{11} = \frac{20}{132} = \frac{5}{33}\).
- #### \(\frac{5}{33}\)
- Question:** Find the limit as \(x \to 0\) of \(\frac{\sin(3x)}{x}\).
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