o hare airport

o oo bo po mo fo.
927 a o e oao 928.
oo1.
o(x)o(x)
2011 1 .
O (n)O (n log n) .
. ,,.. dbzhang800DJ.
0x8007045DI/O CMD Win + R CMD .
byrut.rog byrut
2011 1 .

o oo bo po mo fo.
927 a o e oao 928.
oo1.
o(x)o(x)
2011 1 .
O (n)O (n log n) .
. ,,.. dbzhang800DJ.
0x8007045DI/O CMD Win + R CMD .
byrut.rog byrut
2011 1 .
Remaining: 720 - 410 = 310
Last 3 hours: 310 ÷ 3 ≈ 103.333 — contradiction.
Ah! Here’s the error.
The instruction says: in the next hour walks twice as fast — so third hour: rate ×2 → 120 × 2 = 240 for that hour? But then:
First 2 hours: 120 × 2 = 240
Third hour: 120 × 2 = 240
Total after 3 hours: 240 + 240 = 480
Remaining: 720 - 480 = 240
Then last 3 hours: 240 ÷ 3 = <<240/3=80>>80 per hour.
And 50 more than second hour: second hour at 120, 120 + 50 = 170 ≠ 240 → contradiction.