For $ 3 $: $ \min(2, 4) = 2 $

Related Articles

• Question: What is the greatest common divisor of $ 2^5 \cdot 3^2 \cdot 5 $ and $ 2^3 \cdot 3^4 \cdot 7 $?
• Solution: To find the GCD, take the minimum exponent for each common prime factor:
• For $ 2 $: $ \min(5, 3) = 3 $
• $ 5 $ and $ 7 $ are not common to both.
• Thus, the GCD is $ 2^3 \cdot 3^2 = 8 \cdot 9 = 72 $.
• The greatest common divisor is $ \boxed{72} $.

Trending Articles

Secrets of the Insomnia Crown City MTG Card No One Has FoundUnlock the Best Cod Mw3 Account for Instant Rank UpDolphin Olympics 2: The Jaw-Dropping New Trick That Blew The Judges Awayanthro heat free unlocked: the secret ending you missedCS2 Skull Knife: The One Knife You're Afraid to OpenSan Fierro Map Glitch Lets You Escape GTA’s Hidden Prison—Watch This!The Christmas board game that's secretly on everyone's wishlistHidden Sonic Mania Mods They Don’t Want You To SeeWhy the Insomnia Crown City MTG Card is Officially OPUnlock the Horizon: What Game-Changer Hides in Triclops Drive?