f(-2) = 3(4) + 4 + 1

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• g(2) = 2 - 4 = -2
• Next, substitute into \(f(x)\):
• f(-2) = 3(-2)^2 - 2(-2) + 1
• f(-2) = 12 + 4 + 1 = 17
• A geometric sequence starts with 3 and has a common ratio of 2. What is the 6th term of the sequence?
• The formula for the \(n\)th term is \(a_n = a \cdot r^{n-1}\).

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