C = 2\pi r = 2\pi \left(\frac{5\sqrt{2}}{2}\right) = 5\pi\sqrt{2}
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- d = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}
- The radius \(r\) of the circle is half the diagonal:
- r = \frac{5\sqrt{2}}{2}
- Thus, the circumference of the circle is:
- \boxed{5\pi\sqrt{2}}
- Given a triangle with sides \(7 \, \text{cm}\), \(24 \, \text{cm}\), and \(25 \, \text{cm}\), find the length of the shortest altitude.
