Home / a + b + c + d = (7k + 3) + (7m + 3) + (7n + 3) + (7p + 3) = 7(k + m + n + p) + 12 = 84

a + b + c + d = (7k + 3) + (7m + 3) + (7n + 3) + (7p + 3) = 7(k + m + n + p) + 12 = 84

March 11, 2026

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for integers $ k, m, n, p $. The total is:
Let $ a = 7k + 3 $, same for others. Then sum $ = 7(k + m + n + p) + 12 = 84 $. So:
Unless the problem allows non-congruent? No.
So assume total is 89. But the problem says 84.