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+ c = 6 \\
\( f(0) = 2 \) implies \( r = 2 \).
\( f(1) = 0 \) implies \( 1 + p + q + r = 0 \).
\( f(2) = -2 \) implies \( 8 + 4p + 2q + r = -2 \).
+ p + q + 2 = 0 \\
+ 4p + 2q + 2 = -2 \\
+ 4p + 2q = -2 \\
+ q = -3 \\
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