\( I(3) = a(3)^2 + b(3) + c = 18 \)
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- \( I(1) = a(1)^2 + b(1) + c = 6 \)
- \( I(2) = a(2)^2 + b(2) + c = 11 \)
- \( P(1) = k(1)^2 + m(1) + n = 120 \implies k + m + n = 120 \)
- \( P(2) = k(2)^2 + m(2) + n = 150 \implies 4k + 2m + n = 150 \)
- \( P(3) = k(3)^2 + m(3) + n = 210 \implies 9k + 3m + n = 210 \)
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