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#### 68
February 22, 2026
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#### \( a = 3, b = -12, c = 9 \)
#### \(rac{3}{5}\)1.
\[ S = 15 imes (15 + 1) = 15 imes 16 = 240 \]
\[ b^2 - 4ac = (-5)^2 - 4 imes 2 imes (-3) = 25 + 24 = 49 \]
\[ x = rac{-(-5) \pm \sqrt{49}}{2 imes 2} = rac{5 \pm 7}{4} \]
\[ x = rac{5 + 7}{4} = 3 \quad ext{and} \quad x = rac{5 - 7}{4} = -rac{1}{2} \]
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