\( 19.6s = 1600 \)

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• \( v^2 = u^2 + 2as \), où \(v = 0\), \(u = 40\), \(a = -9.8\), et \(s\) est la hauteur maximale.
• \( 0 = 40^2 + 2(-9.8)s \)
• \( 0 = 1600 - 19.6s \)
• \( s = \frac{1600}{19.6} \approx 81.63 \, \text{m} \)
• #### 81.63
• \( A = P(1 + r)^t \), où \(P = 1000\), \(r = 0.06\), \(t = 5\).

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